A survey was done that asked people to indicate whether they preferred to swim in a pool or in an ocean. The results are shown in the two-way table.

If 609 people were surveyed, what is the relative frequency (rounded to the nearest hundredth) of a person over 30 years old who prefers to swim in the ocean?

hint: you will have to divide the part by the whole

Question 2 options:

.54


.30


.57


.09

A survey was done that asked people to indicate whether they preferred to swim in a pool or in an ocean The results are shown in the twoway table If 609 people class=

Respuesta :

Given:
                                 Pool swimming        Ocean swimming    Total
Age 30 and younger             228                         54                 282
Over 30 years old                142                        185                 327
total                                    370                        239                609

Frequencies:
                                Pool swimming        Ocean swimming    Total
Age 30 and younger     228/609 = 0.37         54/609 = 0.09       282/609 = 0.46
Over 30 years old        142/609 = 0.23       185/609 = 0.30       327/609 = 0.54
total                           370/609 = 0.61       239/609 = 0.39       609/609 = 1.00

The relative frequency (rounded to the nearest hundredth) of a person over 30 years old who prefers to swim in the ocean is 0.30    

Answer: the answer is divide 185 by 609

I chose Divide 239 by 609 and it was the wrong answer.

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