Question

What are the roots to the quadratic equation with the following coefficients in standard form? a=2, b=-3, c=-4

Answer 1

The roots are $\frac{3 +/- \sqrt{41}}{4}$.

You can find the roots of any quadratic using the following equation.

$\frac{-b +/- \sqrt{b^{2}- 4ac}}{2a}$

Now we can place each of the values in their respective spots.

$\frac{3 +/- \sqrt{-3^{2}- 4(2)(-4)}}{2(2)}$

$\frac{3 +/- \sqrt{9 + 32}}{4}$

$\frac{3 +/- \sqrt{41}}{4}$

Then these are your roots.