Explanation:
As we know that according to Avogadro, 1 mole of an atom contains [tex]6.022 \times 10^{23}[/tex] atoms.
So, number of atoms given in the methanol are [tex]9.06 \times 10^{24}[/tex]. Hence, calculate the number of moles present as follows.
No. of moles = [tex]\frac{9.06 \times 10^{24}atoms}{6.022 \times 10^{23} atoms/mol}[/tex]
= 15.04 mol
As molar mass of methanol is 32.04 g/mol. Hence, the mass of given methanol is as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
15.04 mol = [tex]\frac{mass}{32.04 g/mol}[/tex]
mass = 481.28 g
Thus, we can conclude that mass of [tex]9.06 \times 10^{24}[/tex] molecules of methanol ([tex]CH_{3}OH[/tex]) is 481.28 g.
