Question

What volume does .0685 mol of gas occupy at STP? 1mole =22.4

Answer 1

Answer : The volume of gas at STP is, 1.53 liter

Solution : Given,

Moles of a gas = 0.0685 mole

As we know that at STP,

1 mole of gas contains 22.4 liter volume of gas

As, 1 mole of gas contains 22.4 liter volume of gas

So, 0.0685 mole of gas contains $0.0685\times 22.4=1.53L$ volume of gas

Therefore, the volume of gas at STP is, 1.53 liter

Answer 2

We have that for the Question "What volume does 0.0685 mol of gas occupy at STP? 1mole =22.4" it can be said that What volume does 0.0685 mol of gas occupy at STP? 1mole =22.4 is $V=1.5344 L$

From the question we are told

What volume does 0.0685 mol of gas occupy at STP? 1mole =22.4

Generally the equation for the Volume  is mathematically given as

V=Number of moles *22.4mol^{-1}

Therefore

V=0.0685*22.4

$V=1.5344 L$

Therefore

What volume does 0.0685 mol of gas occupy at STP? 1mole =22.4 is $V=1.5344 L$

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