Answer:
Step-by-step explanation:
The given figure is a compound figure with a triangle on top followed by a rectangle below and next below is a trapezium
Hence area of the given figure = area of top triangle +area of middle rectangle+area of bottom trapezium
Area of top triangle= [tex]\frac{1}{2} (bh) (b=base h=height)=\frac{1}{2}(4x3)=6[/tex]
Area of middle rectangle=[tex]bh 3x10=30[/tex]
area of a trapezoid=[tex]\frac{1}{2}h(b_1 +b_2) =\frac{1}{2}(5+3)2 =8[/tex]1/2(base+base)h (two bases because one on top, one on bottom) 1/2(5+3)2=8
Total area = 6+30+8 =44 in^2
