Respuesta :
see the attached picture to better understand the problem
we know that
The opposite angles in a quadrilateral inscribed in a circle are supplementary.
So
in this problem
m∠K+m∠M=[tex] 180 [/tex]
m∠L+m∠N=[tex] 180 [/tex]
Step [tex] 1 [/tex]
Find the measure of angle M
m∠K+m∠M=[tex] 180 [/tex]
m∠M=[tex] 180 [/tex]-m∠K
m∠M=[tex] 180-67 [/tex]
m∠M=[tex] 113 [/tex]°
Step [tex] 2 [/tex]
Find the measure of angle N
m∠L+m∠N=[tex] 180 [/tex]
m∠N=[tex] 180 [/tex]-m∠L
m∠N=[tex] 180-119 [/tex]
m∠N=[tex] 61 [/tex]°
therefore
the answer is
m∠M=[tex] 113 [/tex]°
m∠N=[tex] 61 [/tex]°
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The two angles M and N are m∠M=113° and m∠N=61° when Angle K measures 67º and angle L measures 119°
What are Supplementary angles?
The opposite angles in a quadrilateral inscribed in a circle are supplementary.
in this problem
m∠K+m∠M=180
m∠L+m∠N=180
Step 1
Find the measure of angle M
m∠K+m∠M=180
m∠M=180-m∠K
m∠M=180-67
m∠M=113°
Step 2
Find the measure of angle N
m∠L+m∠N=180
m∠N=180-m∠L
m∠N=180-119
m∠N=61°
m∠M=113° m∠N=61°
Hence the two angles M and N are m∠M=113° and m∠N=61° when Angle K measures 67º and angle L measures 119°
To know more about Supplementary angles follow
https://brainly.com/question/12919120a