Question

solve for x under the assumption that x > 0. x-36/x <-9

Answer 1

$\dfrac{x-36}{x}<-9$
as $x>0$
$x-36<-9x$
$x+9x<36$
$10x<36$
$x<\dfrac{36}{10}$
$\boxed{x<3.6}$