Respuesta :
x+2y=8
2y=-x+8
y=-x/2+4
So for L to be perpendicular to this its slope must be the negative reciprocal of y's slope...
-1m/2=-1, m=2
So L has a slope of 2
L=2x+b, since it passes through the origin its y-intercept is zero so
L=2x or back in y terms
y=2x, by convention you want to arrange this so x has a positive coefficient...
2x-y=0
So B, is the correct answer.
2y=-x+8
y=-x/2+4
So for L to be perpendicular to this its slope must be the negative reciprocal of y's slope...
-1m/2=-1, m=2
So L has a slope of 2
L=2x+b, since it passes through the origin its y-intercept is zero so
L=2x or back in y terms
y=2x, by convention you want to arrange this so x has a positive coefficient...
2x-y=0
So B, is the correct answer.
B) 2x-y=0
You solve for y to get a linear equation. (y=-1/2 x+4) Then you know that perpendicular lines have opposite slopes and it passes through the origin. so in the form y=Mx+B, b is 0, and m is 2. y=2x+0. then subtract y and you get 0=2x-y
You solve for y to get a linear equation. (y=-1/2 x+4) Then you know that perpendicular lines have opposite slopes and it passes through the origin. so in the form y=Mx+B, b is 0, and m is 2. y=2x+0. then subtract y and you get 0=2x-y