Answer: D. [tex]\text{Area of square 1+Area of square 2=Area of square 3 }[/tex]
Step-by-step explanation:
Let the 'h' be the length of the hypotenuse of the right angle, 'a' be the side corresponding to the square 2 and 'b' be the side corresponding to the square 1 .
Since, area of square =[tex](side)^2[/tex]
Then, Area of square 1 = [tex]b^2[/tex]......................(1)
Area of square 2 = [tex]a^2[/tex]......................(2)
Area of square 3 = [tex]h^2[/tex]......................(3)
Using Pythagoras theorem in given right triangle, we get
[tex]h^2=a^2+b^2\\\\\Rightarrow\text{Area of square 3 =Area of square 1+Area of square 2 }[/tex] [from (1),(2) and (3)]
