Question

The ksp of strontium carbonate, srco3, is 5.60 × 10-10. calculate the solubility of this compound in g/l.

Answer 1

The solubility product constant of a compound is calculated by the product of its corresponding ion concentration. The dissociation reaction would be as follows:

SrCO3 = Sr2+ + (CO3)2-

Ksp = [Sr2+] [CO3] = 5.60 × 10^-10
5.60 × 10^-10 = x^2
x = 2.37x10^-5 mol/L = 3.49x10^-3 g/L