Using the form y=a(x-h)²+k
We can look at the vertex (-3,-2) which gives us the values of h,k
h=3, k=-2
Thus y=a(x+3)²-2
Then we can solve for a using any point on the line
- I'll use (-4,-1)
Insert the values of x,y into y=a(x+3)²-2
--> x=-4, y=-1
y=a(x+3)²-2
-1=a(-4+3)²-2
-1=a(-1)²-2
a-2=-1
a=-1+2
a=1
Insert the value of a
y=1(x+3)²-2
= (x+3)²-2
Thus y=(x+3)²-2 is the final equation in standard form
