Question

Which equation has the same solutions as 2x^2+16x-10=0 a) (x+4)^2=-3 b) (x+4)^2=-11 c) (x+4)^2=13 d) (x+4)^2=21

Answer 1

hello here is a solution : 

Answer 2

2x^2 + 16x - 10 = 0
2(x^2 + 8x)  - 10 = 0
2 [(x + 4)^2 - 16 ]- 10 = 0
[(x + 4)^2 - 16 - 5 = 0
(x + 4)^2 - 21 = 0
(x + 4)^2 = 21