Answer with explanation:
As, the log is in the shape of Frustum.We will use the Formula of frustum to find the volume.
A=13 inches,B=11 inches, H=10 feet
Volume of Frustum
[tex]=\frac{\pi\times H}{3}[A^2+B^2+AB]\\\\=\frac{3.14 \times 10}{3}\times[(\frac{13}{2})^2+(\frac{11}{2})^2+\frac{13}{2} \times \frac{11}{2}]\\\\=\frac{31.4}{3} \times [\frac{169}{4}+\frac{121}{4}+\frac{143}{4}]\\\\=\frac{31.4}{3} \times \frac{433}{4}\\\\=1133[/tex]
Ok, when you will round up the numbers, in equation of Volume it will give
Volume of frustum = 3 × 36 × 10 cubic feet(Approximate)
Because ,
[tex]\rightarrow\frac{3.14 \times 10}{3}=10\\\\\rightarrow \frac{169}{4}+\frac{121}{4}+\frac{143}{4}=36 \times 10[/tex]
Option C:
