Question

Calculate the capacitance of a system that stores 2.0 10-10 C of charge at 100.0 V. Use .

Answer 1

Hi there,
So your answer to your question 
A) C=Q/V=(10*10^-6)/10=10^-6 Farads 
B)V=Q/C=100*10^-6/10^-6=100 Volts thanks~Becky

Answer 2

Answer:

Capacitance, $C=2\ pF$

Explanation:

It is given that,

Charge stored in the capacitor, $q=2\times 10^{-10}\ C$

Potential difference, V = 100 V

Capacitance of a system is given by :

$C=\dfrac{q}{V}$

$C=\dfrac{2\times 10^{-10}\ C}{100\ V}$

$C=2\times 10^{-12}\ Farad$

or C = 2 picofarad , c = 12 pF

Hence, the capacitance of the system is $2\ pF$