Respuesta :
Here, we have the limits: 0 ≤ x ≤ 10 and 0 ≤ y ≤ 26
When, x = 0, y = 260/10 = 26
x = 1, y = 250/10 = 25.9
x = 2, y = 258/10 = 25.8
x = 3, y = 257/10 = 25.7
and so on....for x = 10, y = 250/10 = 25
Intercepts would be: (0, 26), (1, 25.9) (2, 25.8) (3, 25.7), (4, 25.6), (5, 25.5) (6, 25.4) (7, 25.3) (8, 25.2), (9, 25.1), (10, 25)
x-coordinate represents the time taken by the athlete, and y represents the distance, he covered in that time.
Hope this helps!
When, x = 0, y = 260/10 = 26
x = 1, y = 250/10 = 25.9
x = 2, y = 258/10 = 25.8
x = 3, y = 257/10 = 25.7
and so on....for x = 10, y = 250/10 = 25
Intercepts would be: (0, 26), (1, 25.9) (2, 25.8) (3, 25.7), (4, 25.6), (5, 25.5) (6, 25.4) (7, 25.3) (8, 25.2), (9, 25.1), (10, 25)
x-coordinate represents the time taken by the athlete, and y represents the distance, he covered in that time.
Hope this helps!
Answer:
The value of x at the start line will be 0.
Substitute 0 = x in the equation:
(0) + 10y = 260
10y = 260
y = 26 miles.