Question

A person gets on a Ferris wheel at the starting point. The starting point is 15 feet off the ground. The Ferris wheel has a radius of 50 feet. What is the height of the rider from the ground after the Ferris wheel rotates 11π/12 radians?

Answer 1

Starting point is at bottom of ferris wheel at -pi/2 radians.

11pi/12 - pi/2 = 5pi/12 radians.

50*sin(5pi/12) = 48.3 feet above center of wheel

48.3 + distance to bottom + height at bottom = 48.3 + 50 + 15 = 113.3 feet

Answer 2

Answer:

Step-by-step explanation:

Given that A person gets on a Ferris wheel at the starting point which is 15 feet off the ground.

BOttom wheel would be making angle with the horizontal diameter an angle equal to -90 degrees or -pi/2

When he rotates an angle of 11 pi/12, from the position -pi/2

angle position at present = 11pi/12-(pi/2) = 5pi/12

Height travelled = r sin theta = 50(5pi/12) =48.3 feet above origin (here centre of wheel)

Height above the ground = 48.3 + radius 50 feet + height of starting point

= 48.3+50+15

= 113.3 feet.