Respuesta :
basically the graphs represent
y=x^2-1 and y=x+1
and where they intersect are the solutions
so just graph each
y=x+1
that has y intercep at y=1
that is 1st graph, 2nd, and 4th graph
now, we got
y=x^2-1
hmm, at x=0, y=-1
so it can't be first or 2nd one
it has to be the 3rd one
the answer is the 3rd one: https://us-static.z-dn.net/files/d6b/8b369670d3f70b5d375515f82d095327.jpg
y=x^2-1 and y=x+1
and where they intersect are the solutions
so just graph each
y=x+1
that has y intercep at y=1
that is 1st graph, 2nd, and 4th graph
now, we got
y=x^2-1
hmm, at x=0, y=-1
so it can't be first or 2nd one
it has to be the 3rd one
the answer is the 3rd one: https://us-static.z-dn.net/files/d6b/8b369670d3f70b5d375515f82d095327.jpg
Answer:
Option 3rd is correct.
Step-by-step explanation:
We have been given an equation:
[tex]x^2-1=x+1[/tex]
We can see that the graphical method gives the solution by intersection of two graphs.
So, one graph is of parabola open upwards
And the right hand side is the straight line.
Option 1 and 2 are discarded being open downwards.
And Option 3rd is correct.
Intersecting at (-1,0) and (2,3).