Respuesta :
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[1-(-2)]^2+[4-(-3)]^2}\implies d=\sqrt{(1+2)^2+(4+3)^2} \\\\\\ d=\sqrt{9+49}\implies d=\sqrt{58}\implies d\approx 7.62[/tex]
Answer:
7.62 units
Step-by-step explanation:
We are given that
The coordinates of point A is at (1,4).
The coordinates of point B is at (-2,-3).
We have to find the approximate distance between A and B.
Distance formula:[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using this formula we will find the distance between A and B.
AB[tex]=\sqrt{(-2-1)^2+(-3-4)^2}[/tex]
Distance between A and B=[tex]\sqrt{49+9}=\sqrt{58}[/tex]
Distance between A and B=[tex]7.62[/tex] units
Hence, the approximate distance between points A and B=7.62 units
Option C is true.