Jane pulled weeds in the garden 7times.she was paid $5 each time she pulled weeds for less than 1 hour and $6 each time she pulled weeds for more than 1 hor.if jane received $39, how many times did she pull weeds for more than 1 hour?
Just by looking at it I can see that the answer is 4 times more than 1 hour and 3 times less than 1 hour 4*$6 = $24 3*$5 = $15 7 times = $39
If you need this for maths class though you need to know how to work it out.
To solve set up and solve a pair of simultaneous equations Let L = less than one hour and M = more than one hour Therefore L + M = 7 (she pulled weeds 7 times) From this L = 7 - M
$5 * L + $6 * M = $39 (rate of pay times number of occasions = total pay) Which mathematically can be written 5L + 6M = 39 BUT we know that L = 7 - M therefore substitutee (7 - M) for "L" in the above equation which now becomes 5(7 - M) + 6M = 39 Expand the bracket 35 - 5M + 6M = 39 Simplify 35 + M = 39
M = 4 As she pulled weeds on 7 occasions and on 4 of these she took more than one hour it follows that on 3 occasions she pulled weeds for less than one hour L = 3
just assume that she did it less than 1 hour x times and more than 1 hour y times so you can get: [tex] \left \{ {{5x+6y=39} \atop {x+y=7}} \right. [/tex] and solve this equation system, you get:[tex] \left \{ {{x=3} \atop {y=4}} \right. [/tex]
