Question

Write an equation of the line that is perpendicular to the line y = 1/3 x + 6 that passes through the point (2,-3).

Answer 1

Hello:
the equation is : y = ax+b
the slope is a : a×(1/3) = -1......( perpendicular to a line  : y = (1/3)x+6 with a slope of 1/3)
a =-3         y=-3x+b
the line that passes through (2, -3) : -3 =- 3(2)+b
b =3
 the equation is :  y  =-3x+3

Answer 2

Answer:

b=3

Step-by-step explanation: