Respuesta :
A = (P/4)(P/2 - P/4)
= (P/4)^2
Therefore it is a square
Playground
256 yd^2
P least perimeter
256 = (P/4)^2
P/4 = √256
= 16
P = 4*16
= 64
The least fencing is 64 yards.
Hope I helped!
Answer:
[tex]x^2- 8x - 256=0[/tex]
Step-by-step explanation:
Let the width of the rectangular park = x
b= x
As the area of the park is given to be 256 Sq yards
length [tex]l=\frac{256}{x}[/tex]
The perimeter of any rectangle is given as
P = 2(length * width )
Hence
[tex]P = 2 ( x + \frac{256}{x})[/tex]
In order to find the perimeter , we need to find the value of x first . In order to find x we have to use the relation which says that length is 8 yards more width of the park.
that is
[tex]\frac{256}{x}=x+8[/tex]
which will give us the quadratic equation. solving that we will get the value of x