The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to the nearest whole number.
56=(x+2)x(2x-5) 56=2x^2-5x+4x-10 56=2x^2-x-10 0=2x^2-x-66(use midterm breaking now) 0=2x^2+11x-12x-66 0=2x(x-6)+11(x-6) So factors are (2x+11) or (x-6) as the length is always positive we chose x-6 so x-6=0..x=6 is the answer thanks now plz select answer as brainliest :)
