Question

A spring of 1 kg is attached to a spring which produces an extension of 0.1 cm its spring constant

Answer 1

F=m·a                                 
F=(1kg)(9.81m/s²)
F=9.81N

0.1cm=0.001m

k=Fs/x
k=9.81N/0.001m
The final answer is k=9810N/m