Question

What is the area of a sector with a central angle of π/3 radians and a radius of 12.4 m?

Use 3.14 for π and round your final answer to the nearest hundredth.

Answer 1

80.15m^2 
is ur answer.

Answer 2

Answer:

The area of the sector is 80.47 m².

Step-by-step explanation:

The area of a sector is

$A=\pi r^2\times \frac{\theta}{360}$

Where, r is radius and θ is central angle in degree.

The radius of the circle is 12.4 m.

Central angle is π/3 radians.

$\theta=\frac{\pi}{3}\times \frac{180}{\pi}=60^{\circ}$

The area of sector is

$A=(3.14)\times (12.4)^2\times \frac{60}{360}$

$A=80.4677\approx 80.47$

Therefore the area of the sector is 80.47 m².