The answer you have highlighted is correct. Here is why
[tex]( \frac{ b^{2}-10 }{b^{2}-9})( \frac{b - 3}{b + 10}) [/tex]
[tex] \frac{(b+10)(b-10)}{(b+3)(b-3)}( \frac{b-3}{b+10}) [/tex] - Factor the top
[tex] \frac{b-10}{b+3} [/tex] - the (b-3)'s and (b+10)'s cancel out since on top and bottom.