Question

A basket contains 8 pieces of fruit: 3 apples, 3 oranges, and 2 bananas. Jonas takes a piece of fruit at random from the basket, and then Beth takes a piece at random. What is the probability that Jonas will get an orange and Beth will get an apple?

Answer 1

As the basket contains 8 pieces of fruits of which 3 are oranges,

the probability that Jonas will get an orange is 3/8.

Considering Jonas has already got an orange, as 7 fruits are left of which 3 are apple, probability that Beth will get an apple will be 3/7.

Hence the probability that Jonas will get an orange and Beth will get an apple is 3/8*3/7=9/56

Answer: 9/56

Answer 2

Answer:

$\frac{9}{56} =16.07$%

Step-by-step explanation:

To solve this you have to remember that probability is calculated by the next formula:

$Probability=\frac{Desired.outcomes}{Possible.outcomes}$

You can calculate the probability of two consequent events by multiplying the probability of each one occuring.

So the first one, you have 8 apple sin the basket and 3 of them are oranges, Jonas has to take out 3 out of 8.

$Jonas=\frac{Desired.outcomes}{Possible.outcomes}\\Jonas=\frac{3}{8}$

Now there are only 7 fruits in the basket, 3 of them are apples, this means that Beth would have to take out 3 out of 7

$Beth=\frac{Desired.outcomes}{Possible.outcomes}\\Beth=\frac{3}{7}$

Now we just have to multiply both probabilities:

$Combined probablilty=(\frac{3}{8}) (\frac{3}{7} )\\Combined probablilty=(\frac{3*3}{8*7})\\Combined probablilty=(\frac{9}{56})$

So the answer would be that there is a $\frac{9}{56}$ probability that Jonas and Beth will get an orange and then an apple, when taking fruit out of the basket.