A number is selected from the set {1, 2, 3, 5, 15, 21, 29, 38, 500}. If equal elemental probabilities are assigned, what is the probability that the number chosen is either less than 29 or odd?
There is a 77.78% probability that the number chosen is less then 29 or is odd. To solve for this, add the probabilities of the expected events and then subtract the remaining values. 6/9 + 6/9 - 2/9 = 0.7777 x 100 = 77.78% This is when all the elemental probabilities are equal. I hope this helps you on your assignment.
