Question

21 points if someone gets it right.

You randomly pull a scrap from a bag of scraps. The bag has 3 red scraps, 4 yellow scraps, and 4 black scraps. After that, you roll a number cube one time

What is the probability of drawing a black scrap then rolling two.

Answer 1

Step-by-step explanation:

11 scraps .... 4 are black    

   chance of a black scrap =   4/11

roll die.... 6 possible outcomes   one is a '2'

   one out of six = 1/6

4/11 * 1/6 = 4/66 = 2/33 = .061

Answer 2

Answer: P(black scrap and rolling 2) = 6.06%

Step-by-step explanation:

     We will divide the wanted outcome by the total number of possible outcomes from both scenarios.

     $\displaystyle \frac{\text{wanted outcome}}{\text{possible outcomes}} =\frac{4\;black\;scraps}{11\;total\;scraps}=\frac{4}{11}$

     $\displaystyle \frac{\text{wanted outcome}}{\text{possible outcomes}} =\frac{\text{rolling a 2}}{\text{six sides on a number cube}}=\frac{1}{6}$

     Next, to find the compounded probability, we will multiply these two fractions by each other, divide, and multiply by 100 to create a percentage.

     $\displaystyle \frac{4}{11} *\frac{1}{6} =\frac{4*1}{11*6}=\frac{4}{66} \approx 0.06060606$

     $0.06060606 * 100 = 6.06\%$