Question

At 8:45 p.m., a jet is located 64 mi due east of a city. A second jet is located 57 mi due north of the city.



To the nearest tenth of a mile, what is the distance between the two jets?



Enter your answer as a decimal in the box.

Answer 1

Use Pythagorean theorem. a^2+b^2=c^2.

If you plot it out, these create a perfect triangle. a=57, b=64.

57^2 = 3249. 64^2 = 4096. a^2+b^2= 7345. Take the square root of 7345 which comes out to be 85.7 miles.