Question

A circuit is made up of a resistor, inductor, and capacitor (and nothing else) connected by wires. The capacitor has a capacitance of 1.2
μ
F, the inductor has an inductance of 6.2 mH, and the resistor has a resistance of 120
Ω
. What is the angular frequency
ω
of oscillations in the circuit in s-1?

Answer 1

To calculate the angular frequency (ω) of oscillations in the circuit, we can use the formula:

ω = 1 / √(LC)

where L is the inductance and C is the capacitance.

Given:

Capacitance (C) = 1.2 μF = 1.2 × 10^(-6) F

Inductance (L) = 6.2 mH = 6.2 × 10^(-3) H

Substituting the values into the formula, we get:

ω = 1 / √(6.2 × 10^(-3) × 1.2 × 10^(-6))

Simplifying the expression under the square root:

ω = 1 / √(7.44 × 10^(-9))

ω = 1 / (2.73 × 10^(-5))

ω ≈ 3.66 × 10^(4) s^(-1)

Therefore, the angular frequency of oscillations in the circuit is approximately 3.66 × 10^(4) s^(-1).