Answer: The correct equation is (D) [tex]8.3-0.6x=11.3.[/tex]
Step-by-step explanation: We are to select the equation that results in a different value of 'x' than the other three equations.
Let us solve the equations one by one.
(A). We have
[tex]8.3=-0.6x+11.3\\\\\Rightarrow -0.6x=8.3-11.3\\\\\Rightarrow -0.6x=-3\\\\\Rightarrow x=\dfrac{3}{0.6}\\\\\Rightarrow x=5.[/tex]
(B) We have
[tex]11.3=8.3+0.6x\\\\\Rightarrow 0.6x=11.3-8.3\\\\\Rightarrow 0.6x=3\\\\\Rightarrow x=\dfrac{3}{0.6}\\\\\Rightarrow x=5.[/tex]
(C) We have
[tex]11.3-0.6x=8.3\\\\\Rightarrow 0.6x=11.3-8.3\\\\\Rightarrow 0.6x=3\\\\\Rightarrow x=\dfrac{3}{0.6}\\\\\Rightarrow x=5.[/tex]
(D) We have
[tex]8.3-0.6x=11.3\\\\\Rightarrow -0.6x=11.3-8.3\\\\\Rightarrow -0.6x=3\\\\\Rightarrow x=-\dfrac{3}{0.6}\\\\\Rightarrow x=-5.[/tex]
Therefore, we see that the solution of the first three equations is x = 5 and the solution of the last equation is x = - 5.
Thus, the equation (D) results in a different value of 'x' when solved.Option (D) is correct.
