Question

A computer randomly selects a number from the given set.

{2, 4, 6, 9, 16, 44, 51, 60, 78}

What is the probability that a number less than 10 is selected?

Enter your answer as a fraction, in simplest form, in the box.
P(< 10) =

Answer 1

Answer:  The required probability is $P(<10)=\dfrac{4}{9}.$  

Step-by-step explanation: Given that a computer randomly selects a number from the following set:

{2, 4, 6, 9, 16, 44, 51, 60, 78}.

We are to find the probability that a number less than 10 is selected.

Let, 'S' be the sample space and 'A' be the event that a number less than 10 is selected.

So,

S = {2, 4, 6, 9, 16, 44, 51, 60, 78},

A={2, 4, 6, 9}.

That is, n(S) = 9,  n(A) = 4.

Therefore, the required probability of selecting a number less than 10 is

$P(A)=P(<10)=\dfrac{n(A)}{n(S)}=\dfrac{4}{9}.$

Thus, the required probability is  $P(<10)=\dfrac{4}{9}.$  

Answer 2

The probability that a number less than 10 is selected is; 4/9

Probability Selection

The numbers listed in the given set are;

{2, 4, 6, 9, 16, 44, 51, 60, 78}

The total numbers in the given set are 9 in number.

The total numbers that are less than 10 are 4 in number.

Thus, probability of selecting a a number less than 10 is;

P(less than 10) = 4/9

Read more about probability selection at; https://brainly.com/question/251701