Question

A six-sided number cube is tossed and a coin is flipped.

The sample space is {1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}.


What is the probability of rolling a number greater than 2 and flipping heads?


Enter your answer, as a fraction in simplest form, in the box

Answer 1

Answer: The answer is 1/3, on the third attempt on the quiz, that's what it said.

Answer 2

Answer:  The required probability is $\dfrac{1}{3}.$

Step-by-step explanation:  Given that a six-sided number cube is tossed and a coin is flipped.

We are to find the probability of rolling a number greater than 2 and flipping heads.

The sample space for the event is

S =  {1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}.

That is, n(S) = 12.

Let, 'A' denotes the event of rolling a number greater than 2 and flipping heads.

So, A = {3H, 4H, 5H, 6H}

That is, n(A) = 4.

Therefore, the probability of rolling a number greater than 2 and flipping heads is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{4}{12}=\dfrac{1}{3}.$

The required probability is $\dfrac{1}{3}.$