Respuesta :
The chemical reaction of NaCl going through electrolysis is:
2Na+ + 2Cl- --> 2Na(s) + Cl2
Two electrons are transferred.
All we need to do is use stoichiometry to solve for the amount of charge transferred
1000 g Na ( 1 mol / 23 g) X (2 mols e- / 1 mol Na) X ( 96500 C / 1 mol e-) = 8.39 x 10^6 C
Current is C/s and so we must divide our charge by the time which is one hour, or 3600 seconds:
8.39x10^6 C / 3600 s = 2331 amps.
I hope this helps! Good luck :)
2Na+ + 2Cl- --> 2Na(s) + Cl2
Two electrons are transferred.
All we need to do is use stoichiometry to solve for the amount of charge transferred
1000 g Na ( 1 mol / 23 g) X (2 mols e- / 1 mol Na) X ( 96500 C / 1 mol e-) = 8.39 x 10^6 C
Current is C/s and so we must divide our charge by the time which is one hour, or 3600 seconds:
8.39x10^6 C / 3600 s = 2331 amps.
I hope this helps! Good luck :)
The magnitude of the current produced by the metal of 1 kg has been 2330.9 A.
In electrophoresis, the transfer of 2 moles of electrons takes place per mole of Na.
The moles of sodium has been:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of Na = [tex]\rm \dfrac{1000}{23}[/tex] mol
Moles of Na = 43.47 mol
1 mole Na have = 2 moles electrons transfer
The total charge transfer in 1000 grams Na can be given by:
q = moles of Na [tex]\times[/tex] moles of electrons transfer [tex]\times[/tex] Faraday constant
q = 43.47 [tex]\times[/tex] 2 [tex]\times[/tex] 96500
q = 8.391 [tex]\rm \times\;10^6[/tex] C
The current can be given by:
I = [tex]\rm \dfrac{q}{t}[/tex]
I = [tex]\rm \dfrac{8.39\;\times\;10^6}{3600}[/tex]
I = 2330.9 A
The magnitude of the current produced by the metal of 1 kg has been 2330.9 A.
For more information about current, refer to the link:
https://brainly.com/question/15547654
