Question

when 5.0 of cacl2 dissolves in 50.0g of water, what is the boiling point of the solution?

Answer 1

100+7.8=107.8 degrees. Which is now your new boiling point.

Answer 2

The boiling point will be 101degreeC.

What is boiling point?

The temperature throughout where a liquid's vapor pressure reaches the pressure around it as well as as the liquid transforms into a vapor is known as the boiling point of a substance.

Calculation of boiling point

Given data:

Mass = 50 g

Mol = 5 mol.

Boiling point can be calculated by the formula:

Δ$T_{b}$ = $K_{b} m$

where, Δ$T_{b}$ is boiling point and m is mole.

m = mol/kg

m = 1.25 mol/ 1.4 kg

m = 0.89 m

Now, calculate the value of cacl2 ionized particle.

Cacl2 = $Ca^{+2} +Cl^{-1}$

Cacl2  = 3 particles will be ionized.= 3 ×  0.89 m = 2.67 m

Now, put the value of given data in above equation.

Δ$T_{b}$ = $K_{b} m$

Δ$T_{b}$ = 0.512 × 2.67m

Δ$T_{b}$ = 1.37 degree C.

Now, $100^{0}C + 1.37 ^{0} C = 101^{0}C$

Therefore, the boiling point will be 101degreeC.

To know more about boiling point.

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