Question

In triangle OPQ, the measure of angle Q=90°, OQ=33, PO= 65, and QP= 56. What ratio represents the tangent of angle P?

Answer 1

Answer:

$\sf Tan \ P = \dfrac{33}{56}$

Step-by-step explanation:

Trigonometry ratios:

         

        $\sf Tan \ P = \dfrac{opposite \ side \ of \ \angle P}{adajcent \ side \ of \ \angle P}$

                   $\sf =\dfrac{QO}{QP}\\\\\\=\dfrac{33}{56}$