Question

Can someone please help me answer this what is 1 over x-5 subtract 19-2x over (x-5)(x+4)

Answer 1

$\frac{1}{x - 5} - \frac{19 - 2x}{(x - 5)(x + 4)}$
$\frac{1(x - 5)(x + 4)}{(x - 5)(x + 4)} - \frac{19 - 2x}{x - 5)(x + 4)}$
$\frac{1(x^{2} + 4x - 5x - 20) }{ x^{2} + 4x - 5x - 20} - \frac{19 - 2x}{x^{2} + 4x - 5x - 20}$
$\frac{ x^{2} - x - 20 }{ x_{2} - x - 20} - \frac{19 - 2x}{ x^{2} - x - 20 }$
$\frac{ x^{2} + x + 1}{ x^{2} - x - 20 }$
$-x - \frac{1}{20}$