Answer:
See below!
Explanation:
Force = F = 50 N
Angle = θ = 38.8°
Horizontal and vertical components of force = ?
[tex]F_x=Fcos \theta\\\\F_y=Fsin \theta[/tex]
Horizontal component of force:
[tex]F_x=(50)cos38.8\\\\F_x=(50)(0.77)\\\\F_x\approx 38.9[/tex]
Vertical component of force:
[tex]F_y=(50)sin(38.8)\\\\F_y=(50)(0.62)\\\\F_y\approx 31.3\\\\\rule[225]{225}{2}[/tex]