Respuesta :
Here, y = x - 3
2x + 4y = 12
Substitute it in the equation,
2x + 4(x - 3) = 12
2x + 4x - 12 = 12
6x = 12 + 12
x = 24/6
x = 4
Then, y = x-3 = 4-3 = 1
In that case, your solution would be: (4, 1)
But it is not in the option, so you could choose directly by substitution and can check one by one:
Solution = (8, -1)
Can check in both equations,
2(8) + 4(-1) = 16 - 4 = 12 = R.H.S
Hope this helps!
2x + 4y = 12
Substitute it in the equation,
2x + 4(x - 3) = 12
2x + 4x - 12 = 12
6x = 12 + 12
x = 24/6
x = 4
Then, y = x-3 = 4-3 = 1
In that case, your solution would be: (4, 1)
But it is not in the option, so you could choose directly by substitution and can check one by one:
Solution = (8, -1)
Can check in both equations,
2(8) + 4(-1) = 16 - 4 = 12 = R.H.S
Hope this helps!
we have
[tex]2x+4y=12[/tex] ------> equation A
[tex]y=x-3[/tex]------> equation B
Substitute equation B in equation A
[tex]2x+4[x-3]=12[/tex]
solve for x
[tex]2x+4x-12=12[/tex]
combine like terms
[tex]6x=24[/tex]
[tex]x=4[/tex]
Find the value of y
[tex]y=x-3[/tex]
[tex]y=4-3=1[/tex]
therefore
The answer is
the solution to the system of equations is the point [tex](4,1)[/tex]