Respuesta :
Answer:
option (3) is correct.
[tex]\Rightarrow (x+2)=0[/tex] or [tex]\Rightarrow (x+4)=0[/tex]
Step-by-step explanation:
Given quadratic equation [tex]x^2+6x+8=0[/tex]
We have to choose a valid conclusion for the problem [tex]x^2+6x+8=0[/tex]
Consider the given quadratic equation [tex]x^2+6x+8=0[/tex] .
We can solve the quadratic equation using middle term split,
6x can be written as 2x +4x , thus equation becomes,
[tex]x^2+6x+8=0[/tex]
[tex]\Rightarrow x^2+2x+4x+8=0[/tex]
Taking x common from first two term and 4 common from last two terms, we have,
[tex]\Rightarrow x(x+2)+4(x+2)=0[/tex]
[tex]\Rightarrow (x+4)(x+2)=0[/tex]
Using zero product property, [tex]a\cdot b=0 \Rightarrow a=0 \ or \ b=0[/tex] ,we have,
[tex]\Rightarrow (x+2)=0[/tex] or [tex]\Rightarrow (x+4)=0[/tex]
Thus, option (3) is correct.