Respuesta :

n(Cu) = 7.8x10^21/6.02x10^23
n(Cu)=0.013moles of copper

Explanation:

According to mole concept, 1 mole of every substance contains [tex]6.02 \times 10^{23}[/tex] atoms or molecules.

As number of atoms present in given copper are [tex]7.8 \times 10^{21}[/tex] atoms. Therefore, calculate the number of moles present in this copper atom as follows.

       No.of moles = [tex]\frac{7.8 \times 10^{21}}{6.02 \times 10^{23}}[/tex]

                            = [tex]1.29 \times 10^{-2}[/tex]

                            = 0.0129 mol

Thus, we can conclude that there are 0.0129 moles of copper present in [tex]7.8 \times 10^{21}[/tex] atoms.

ACCESS MORE
EDU ACCESS