Respuesta :

Answer:

Hence, the height of the oblique cylinder to the nearest tenth is:

h=14.7 mm.

Step-by-step explanation:

We are given:

The volume(V) of the oblique cylinder is 5,588 mm3.

if the radius(r) is 11 mm.

Let h denotes the height of the cylinder.

We know that volume of a cube is given as:

[tex]V=\pi r^2h[/tex]

Now we have:

[tex]V=5588 mm^3 , r=11mm[/tex]

⇒  

[tex]5588=\pi (11)^2\times h\\\\h=\dfrac{5588}{\pi \times (11)^2}\\\\h=\dfrac{5588}{3.14\times (11)^2}\\\\h=\dfrac{5588}{379.94}\\\\h=14.7075[/tex]

Hence, the height of the oblique cylinder to the nearest tenth is:

h=14.7 mm.

The height of the cylinder with a radius of 11mm and volume of 5588 mm³ comes to be 14.7 mm.

What is the volume of a cylinder?

The volume of a cylinder is πr²h where r and h have usual notations.

Given the volume of the oblique cylinder =5588 cubic mm

Radius r =11 mm

So, [tex]\pi r^{2} h=5588[/tex]

[tex]\pi 11^{2} h=5588[/tex]

[tex]h=14.69[/tex]≈14.7 mm

So, the height of the cylinder =14.7 mm

Thus, the height of the cylinder comes to be 14.7 mm.

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https://brainly.com/question/9554871

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