Respuesta :
Answer:
Hence, the height of the oblique cylinder to the nearest tenth is:
h=14.7 mm.
Step-by-step explanation:
We are given:
The volume(V) of the oblique cylinder is 5,588 mm3.
if the radius(r) is 11 mm.
Let h denotes the height of the cylinder.
We know that volume of a cube is given as:
[tex]V=\pi r^2h[/tex]
Now we have:
[tex]V=5588 mm^3 , r=11mm[/tex]
⇒
[tex]5588=\pi (11)^2\times h\\\\h=\dfrac{5588}{\pi \times (11)^2}\\\\h=\dfrac{5588}{3.14\times (11)^2}\\\\h=\dfrac{5588}{379.94}\\\\h=14.7075[/tex]
Hence, the height of the oblique cylinder to the nearest tenth is:
h=14.7 mm.
The height of the cylinder with a radius of 11mm and volume of 5588 mm³ comes to be 14.7 mm.
What is the volume of a cylinder?
The volume of a cylinder is πr²h where r and h have usual notations.
Given the volume of the oblique cylinder =5588 cubic mm
Radius r =11 mm
So, [tex]\pi r^{2} h=5588[/tex]
[tex]\pi 11^{2} h=5588[/tex]
[tex]h=14.69[/tex]≈14.7 mm
So, the height of the cylinder =14.7 mm
Thus, the height of the cylinder comes to be 14.7 mm.
To get more about cylinders visit:
https://brainly.com/question/9554871