TSmith4 TSmith4
  • 29-03-2017
  • Mathematics
contestada

Prove that sequence an = (3^n)/(2n)! is monotone

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LammettHash
LammettHash LammettHash
  • 29-03-2017
When [tex]n=1[/tex], you have [tex]a_1=\dfrac3{2!}=\dfrac32[/tex].

When [tex]n=2[/tex], you have [tex]a_2=\dfrac{3^2}{4!}=\dfrac38[/tex].

Clearly, [tex]a_1>a_2[/tex].

Assume [tex]a_k<a_{k-1}[/tex]. Now when [tex]n=k+1[/tex], you have

[tex]a_{k+1}=\dfrac{3^{k+1}}{(2k+2)!}=\dfrac3{(2k+2)(2k+1)}\times\dfrac{3^k}{(2k)!}=\dfrac3{(2k+2)(2k+1)}a_k<a_k[/tex]

Therefore by induction the sequence is monotone (decreasing).
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