Question

Find the value of K such that kx^2+12x-4=0 has one real number solution. Explain

Answer 1

kx^2+12x-4=0
               +4  +4
kx^2+12x=-4
         -12x   -12x
kx^2=-4-12x
square root kx^2 to get kx and square root -4-12x too
kx=the square root of -4-12x
then divide x to both sides and u get ur answer

Answer 2

kx^2+12x-4=0
+4 +4
kx^2+12x=-4
-12x -12x
kx^2=-4-12x
square root kx^2 to get kx and square root -4-12x too
kx=the square root of -4-12x
then divide x to both sides and u get your answer
X=-3

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