Question

If the sin 60° is square root 3 over 2, then the cos ____° = _____.

Answer 1

Cos0=1
Cos30=root3/2
Cos45=root2/2
Cos60= 1/2
Cos90=0

I didn't know which primary angle you wanted, so I gave you all of them :)

Answer 2

The value of cosine of 30 and 60 is $\dfrac{\sqrt3}{2}$ and $\dfrac{1}{2}$, resectively.

Given information:

The value of sin 60° is square root 3 over 2. It can be written as,

$sin60=\dfrac{\sqrt3}{2}$.

From the given information, we can calculate the cosine of 60 degrees and cosine of 30 degrees.

Use the properties of sine and cosine to find the required values as,

$sin^2\theta+cos^2\theta=1\\sin^260+cos^260=1\\(\dfrac{\sqrt3}{2})^2+cos^260=1\\cos60=\dfrac{1}{2}$

Also,

$sin60=sin(90-30)\\=cos30\\=\dfrac{\sqrt3}{2}$

Therefore, the value of cosine of 30 and 60 is $\dfrac{\sqrt3}{2}$ and $\dfrac{1}{2}$, resectively.

For more details, refer to the link:

https://brainly.com/question/10014799