Question

Two quadratic functions are shown.

Function 1:
f(x) = 4x2 + 8x + 1
Function 2:
x g(x)
−2 2
−1 0
0 2
1 8


Which function has the least minimum value and what are its coordinates?
Function 1 has the least minimum value and its coordinates are (−1, −3).
Function 1 has the least minimum value and its coordinates are (0, 1).
Function 2 has the least minimum value and its coordinates are (−1, 0).
Function 2 has the least minimum value and its coordinates are (0, 2).

Answer 1

$\bf \qquad\qquad\textit{vertex of a parabola}\\ \quad \\ \begin{array}{llcclll} f(x)=&4x^2&+8x&+1\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$