Question

A squirrel jumps down from a tall tree. Assuming the squirrel is in free fall, how far will it have fallen in 1.5 seconds?

Answer 1

d = 1/2gt^2 <-- free fall formula

d = (0.5)(9.81)(1.5^2)
d = 11.03625
d = 11.04 m

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Answer 2

Answer:

d = 11.025 m

Explanation:

Since the situation is considered to be free fall so here given data as

initial speed = 0 m/s as it starts from rest

acceleration = 9.8 m/s/s

time of fall = 1.5 s

now we know from kinematics

$d = v_i t + \frac{1}{2}at^2$

$d = 0 + \frac{1}{2}(9.8)(1.5)^2$

$d = 11.025m$

so the distance traveled by the squirrel when it jumps from the tall tree is given as d = 11.025 m