Answer:
The value of f(6) is 18.
Step-by-step explanation:
Given expression,
[tex]f(x)=\frac{x^2}{3}+x-----(1)[/tex]
For finding the value of f(6),
Put x = 6 in equation (1),
[tex]f(6)=\frac{6^2}{3}+6[/tex]
[tex]=\frac{36}{3}+6[/tex]
[tex]=12+6[/tex]
[tex]=18[/tex]
Hence, the value of f(6) is 18 for the given expression.