u(pkx) pkkool pH = pkk + f pkx =pH-f dokłachme 4A=4A = AA²=0,0001 41=6,001 M (PKK) = (20 μ(4)| = (0²0/ 12pk₂ (5) A-A² (22-1)0,509 T f = log AK-A 1+√T ' - og A2-A A-AK (22-1)0,509 1+√7 + 24 124 4**)²-(3²2-4x²)² · (34-40)² · (21 41)² = [0] + + u (f) 2At 2A pk₂ =pH-f' (pk₂) = μ(f¹)| 12+1 F M(F) -√(3 44^)² + (21 44²)² + (3A" 44)² + (3+² 41/² · 21
