Answer:
coordinates of R are (-7,0)
Step-by-step explanation:
It is given that a line segment is PR and Q is the mid point of the PR.
Coordinates of P are (5,6) and Q (-1,3) then we have to find the coordinates of R (x, y).
x coordinates of R will be -1 = [tex]\frac{x+5}{2}[/tex]
-2 = x + 5
x = -2 - 5
x = -7
y coordinates of R will be 3 = [tex]\frac{y+6}{2}[/tex]
6 = y + 6
y = 6 + 6
y = 0
Therefore, coordinates of R are (-7,0)